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28x^2+38x-6=0
a = 28; b = 38; c = -6;
Δ = b2-4ac
Δ = 382-4·28·(-6)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-46}{2*28}=\frac{-84}{56} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+46}{2*28}=\frac{8}{56} =1/7 $
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